Work function of lithium and copper are respectively 2.3 eV and 4.0 eV. Which one of the metal will be useful for the photoelectric cell working with visible light? (h = 6.6 × × 10 –34 J-s, c = 3 × × 10 8 m/s)
Text Solution
Verified by ExpertsThe correct answer is:
A
From 
The maximum wavelength of light required for the photoelectron emission,
Similarly 
.
Since the wavelength 
does not in the visible region, but it is in the ultraviolet region. Hence to work with visible light, lithium metal will be used for photoelectric cell.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A beam of protons with a cross-sectional area of is moving with a velocity of . Then charge dens…
A particle of mass at rest decays into two particles of masses and , having non-zero velocities.…
An image of the sun is formed by a lens of focal length of 30 cm on the metal surface of a photoele…
When an inert gas is filled in the place vacuum in a photocell, then
A photon of 1.7 × × 10 -13 Joules is absorbed by a material under special circumstances. The correc…
The maximum velocity of an electron emitted by light of wavelength incident on the surface of a me…